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Chat Area => General Discussion Area => Topic started by: chrisgixer on 17 November 2013, 15:24:17
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Dara O'Briens schools of hard sums. What have I missed?
A glass of white wine. A glass of Red wine.
Take a small tumbler, fill from red wine glass and poor it into the white wine.
Then take fill the tumbler from the white wine glass and poor it back into the red glass.
Question is. Is the more red in the white glass? Or more white in the red glass?
Answer. Its the same.
Are they right?
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10 views and no replies.
Pussies. ;D
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I've always bin no good at maffs. :)
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My gut feeling was the diluted wine out of second glass would make the red wine less in the first glass.
Then I worked an example and assumed the tumbler holds exactly half the wine glass, the red wine was Rioja and the White a crisp Chardonnay and concluded:
Red wine glass has two thirds red and one third white and white wine glass has two thirds white one third red.
I might be wrong. I might try a practical test tonight when I have my curry. ;D ;D
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To me, it's what is in the tumbler as it crosses over.
The first pass, holds pure red wine, as it goes into the white wine glass.
The second pass, holds a combination of both, as it replaces the same amount if fluid back into the red.
There in lies the difference. IMO.
Where as the programme states that the amount of fluid is the same in each. Which it is. So the amount of red and white must be the same. Not so.
I think the programme is wrong. But then I'm shit at maths. ;D
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Dara O'Briens schools of hard sums. What have I missed?
A glass of white wine. A glass of Red wine.
Take a small tumbler, fill from red wine glass and poor it into the white wine.
Then take fill the tumbler from the white wine glass and poor it back into the red glass.
Question is. Is the more red in the white glass? Or more white in the red glass?
Answer. Its the same.
Are they right?
Well, thats going to make bloody mess to start with....all over the floor/carpet ::)
How can you add more wine to glass of wine ::) :D (A glass of wine, to me, means its full)
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[quote author=Taxi Driver link=topic=119396.msg1515701#msg1515701 date=1384712220
Well, thats going to make bloody mess to start with....all over the floor/carpet ::)
How can you add more wine to glass of wine ::) :D (A glass of wine, to me, means its full)
[/quote]
Exactly! ;)
Someone ain't throwin' straight dice here ... ::)
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I'm guessing with Gixer bein illiterate an all, he ain't explained it right. ;D
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I'm guessing with Gixer bein illiterate an all, he ain't explained it right. ;D
... like a piece of da jigsaw's missin' ???
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I'm guessing with Gixer bein illiterate an all, he ain't explained it right. ;D
... like a piece of da jigsaw's missin' ???
A perfect description of the boy ;D ;D
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While we wait for Chris, I think I have invented a new wine.
I am going to call it Rose (with an accent on that last e, pronounced Rose ehh). Not bad either. Curry will be ready in 30 minutes time :y
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Dara O'Briens schools of hard sums. What have I missed?
A glass of white wine. A glass of Red wine.
Take a small tumbler, fill from red wine glass and poor it into the white wine.
Then take fill the tumbler from the white wine glass and poor it back into the red glass.
Question is. Is the more red in the white glass? Or more white in the red glass?
Answer. Its the same.
Are they right?
Both the same - none in either.
hic.
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serious answer.
let a=capacity of wine glass
let b= capacity of tumbler.
step 1.
We have A ml white wine in glass x
We have A ml of red wine in glass y
Step 2.
Glass x now holds A ml of white wine + B ml of red wine.
glass y now holds A-B ml of red wine.
Step 3
We pour B ml of the mixed wine back into glass y
so glass y now holds ((A-B) + (BxB/A+B))ml of red wine PLUS (AxB/A+B)ml white wine.
Glass X now holds (A-B)ml mixture, of which (B/A+B) is white wine.
so glass Y has (AxB/A+B) of white
glass X has (A-B)(B/A+B) of white
AB/A+B is not the same as (AB-B2)/A+B except when B=0, so therefore, the question to the question, *as stated* is:
NO, they don't hold the same amount of white wine
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Ffs. Fill the tumbler. When its full, stop pooring. Idiots! ;D
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serious answer.
let a=capacity of wine glass
let b= capacity of tumbler.
step 1.
We have A ml white wine in glass x
We have A ml of red wine in glass y
Step 2.
Glass x now holds A ml of white wine + B ml of red wine.
glass y now holds A-B ml of red wine.
Step 3
We pour B ml of the mixed wine back into glass y
so glass y now holds ((A-B) + (BxB/A+B))ml of red wine PLUS (AxB/A+B)ml white wine.
Glass X now holds (A-B)ml mixture, of which (B/A+B) is white wine.
so glass Y has (AxB/A+B) of white
glass X has (A-B)(B/A+B) of white
AB/A+B is not the same as (AB-B2)/A+B except when B=0, so therefore, the question to the question, *as stated* is:
NO, they don't hold the same amount of white wine
Bigegg. If we need to tell people to stop pooring when a glass is full, we have no chance. ;D
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There is no way of calculating it unless you assume they are perfectly mixed, so is this a given assumption?
Likewise you would also have to assume that all of the wine was poured from the red glass and the tumbler, so they were both completely dry.
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Ffs. Fill the tumbler. When its full, stop pooring. Idiots! ;D
I blame the wine :P
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In the original question you said "fill from red wine glass and poor it into the white wine"
NOT the "white wine glass"
:P :P :P
and besides, a wine glass is NEVER filled to the brim, so that the aroma has chance to develop above the liquid.
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No complicated maths, both glasses have the same amount of wine in them, 1 tumbler removed from glass one and then replaced, therefore each has as much of the other colour in it. If one had more than the other it would have gained some volume. Ratio makes no difference as far as I can see.
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No complicated maths, both glasses have the same amount of wine in them, 1 tumbler removed from glass one and then replaced, therefore each has as much of the other colour in it. If one had more than the other it would have gained some volume. Ratio makes no difference as far as I can see.
See, that's my point.
Take a tumbler of red and poor it into the white. This means you've pored a tumbler full of 100% red into the whit glass.
Now, you have a pink "Rose" white wine glass. Yes? So there MUST be some red in the tumbler when returning the same amount of fluid from the white glass to the red.
Therefor there MUST be more red wine in the white glass than there is white wine in the red glass.
Yes the total volume is the same, but that is NOT the question. That being, after pooring a tumbler of red into the white, THEN poring a tumbler from the white(pink) back to the red, is the more red in the white, or more white in the red...?
Just to repeat, they said the answer was, as you say, the same. Same total volume yes. But not the same ratio. Proof being in the colour.
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If the tumbler is the same size as the CONTENT of the wine glass then ALL the red goes into the white then half the rose goes back into the red glass. It is NOT the size of the wine glass that matters, but the amount of wine in it at the start ..... :)
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If the tumbler is the same size as the CONTENT of the wine glass then ALL the red goes into the white then half the rose goes back into the red glass. It is NOT the size of the wine glass that matters, but the amount of wine in it at the start ..... :)
It's not. Tumbler is smaller. Wine glass is bigger.
Tumbler being about the size of a sherry glass. Or roughly 10% the volume of the wine glass.
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Actually. The tumbler is not important.
Just poring 10% into one! then back again. Would give the same result. Provided the amount was accurate. (Hence the tumbler)
The result being, which ever is pored first looses most, and must receive less of its own colour back. As its now mixed. Even though the total volume will be the same when finished.
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Judging by the state of your spelling as this thread gets longer Chris, there can't be much left of either Red or bloody White! Or are you seeing the world through Rosé tinted glasses :-\ ;D ;)
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If both glasses have the same amount of wine at the end then however much red had gone into the white must be the same as white into the red. When I said ratio doesn't matter I meant that the ratio will be different between the 2 glasses, ie opposite. If at the end there is only 60% of the red left in the red glass then there must be 40% white and vice versa, 20% red left then it's 80% white and vice versa.
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If both glasses have the same amount of wine at the end then however much red had gone into the white must be the same as white into the red. When I said ratio doesn't matter I meant that the ratio will be different between the 2 glasses, ie opposite. If at the end there is only 60% of the red left in the red glass then there must be 40% white and vice versa, 20% red left then it's 80% white and vice versa.
If the first tumbler pored has 100% red, then the second can not possibly have 100% white. Therefor, there's more red in the white glass. No?
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If both glasses have the same amount of wine at the end then however much red had gone into the white must be the same as white into the red. When I said ratio doesn't matter I meant that the ratio will be different between the 2 glasses, ie opposite. If at the end there is only 60% of the red left in the red glass then there must be 40% white and vice versa, 20% red left then it's 80% white and vice versa.
If the first tumbler pored has 100% red, then the second can not possibly have 100% white. Therefor, there's more red in the white glass. No?
You do know that people like to wind you up over tyres, wine glasses and the like...........don't you? ;D
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Judging by the state of your spelling as this thread gets longer Chris, there can't be much left of either Red or bloody White! Or are you seeing the world through Rosé tinted glasses :-\ ;D ;)
Always ;D
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If both glasses have the same amount of wine at the end then however much red had gone into the white must be the same as white into the red. When I said ratio doesn't matter I meant that the ratio will be different between the 2 glasses, ie opposite. If at the end there is only 60% of the red left in the red glass then there must be 40% white and vice versa, 20% red left then it's 80% white and vice versa.
If the first tumbler pored has 100% red, then the second can not possibly have 100% white. Therefor, there's more red in the white glass. No?
You do know that people like to wind you up over tyres, wine glasses and the like...........don't you? ;D
You don't know the answer either then Esta. ::) ;)
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If both glasses have the same amount of wine at the end then however much red had gone into the white must be the same as white into the red. When I said ratio doesn't matter I meant that the ratio will be different between the 2 glasses, ie opposite. If at the end there is only 60% of the red left in the red glass then there must be 40% white and vice versa, 20% red left then it's 80% white and vice versa.
If the first tumbler pored has 100% red, then the second can not possibly have 100% white. Therefor, there's more red in the white glass. No?
You do know that people like to wind you up over tyres, wine glasses and the like...........don't you? ;D
You don't know the answer either then Esta. ::) ;)
The correct answer was given on the TV programme, I'm assuming. Think I'd trust their maths against yours most days. ;D
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Second tumbler ratio doesn't matter as long as both glasses have the same volume left at the end. You can ignore the ratio, it just doesn't matter. All that matters is the fact both glasses have the same volume at the end. Therefore whatever % red is in one glass must be the same as white in the other.
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If both glasses have the same amount of wine at the end then however much red had gone into the white must be the same as white into the red. When I said ratio doesn't matter I meant that the ratio will be different between the 2 glasses, ie opposite. If at the end there is only 60% of the red left in the red glass then there must be 40% white and vice versa, 20% red left then it's 80% white and vice versa.
If the first tumbler pored has 100% red, then the second can not possibly have 100% white. Therefor, there's more red in the white glass. No?
You do know that people like to wind you up over tyres, wine glasses and the like...........don't you? ;D
You don't know the answer either then Esta. ::) ;)
The correct answer was given on the TV programme, I'm assuming. Think I'd trust their maths against yours most days. ;D
So would I, normally. Except there's NO MATHS INVOLVED. ;D
Oh well. At least you and I are as thick as each other. Clearly.
No wait, I'm putting myself down here ;D
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to explain it mathematically .. and using simple numbers .. If the wine glass holds 100 ml and the tumbler holds 20 ml ..
both wine glasses intially hold 100 ml red / white respectively.
take 20 ml red out of the red glass - it holds 80 ml now
pour the 20 ml into the 100 white .. you have 120 ml of which 20 is red, so is 100 is white .. so it is 83% white and 17% red (100/120 * 100 white 20/120 * 100 red)
pour 20 ml out of that glass into the tumbler .. what REMAINS in the "white glass" is still 83% white 17% red
the 20 ml in the tumbler is also 83% / 17% so contains 17 ml white and 3 ml red
pour that into the 80 ml red and you have
80 + 3 ml red - 83 + 17 ml white ... so 83% red and 17% white
so there is the a same amount of red wine in the white glass as there is white wine in the red glass .. which is what the original question asks if you read it properly .. it never says the amount of red and white is the same
"Is there more red in the white glass? Or more white in the red glass?"
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so there is the a same amount of red wine in the white glass as there is white wine in the red glass .. which is what the original question asks if you read it properly .. it never says the amount of red and white is the same
"Is there more red in the white glass? Or more white in the red glass?"
You can't just go around reading the question properly, and then making rational statements based on it.
This is the *internet*
::)
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So a ratio of 4:1 at all times.
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So a ratio of 4:1 at all times.
(Waits for a smart arse reply from Esta, like he knew all along. ;D)
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so there is the a same amount of red wine in the white glass as there is white wine in the red glass .. which is what the original question asks if you read it properly .. it never says the amount of red and white is the same
"Is there more red in the white glass? Or more white in the red glass?"
You can't just go around reading the question properly, and then making rational statements based on it.
This is the *internet*
::)
Quite right Humpty :y
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Just drink both glasses ....... ::) ::)
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Just drink both glasses ....... ::) ::)
In the school of hard drinking, yes, Mr B. ;)
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So a ratio of 4:1 at all times.
Ratio will depend on how big the tumbler is, point being the ratio in one glass will be opposite the other, ie same amount of red in the white glass as white in the red.
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Have just checked and it works with vodka and a mixer too ;D
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Have just checked and it works with vodka and a mixer too ;D
Anything goes in the name of research. :y ;D