Okies .. to "redo" TB's calculations ... as best I can and hopefully I've got it right .....
1500 cc of air per revolution @ 600 rpm (idle) = 900000 = 900 ltrs air /minute
Relative density of air is 0.0013 kg/ltr
so 900 X .0013 =1.17 kg of air /minute
"perfect" ratio of 14.7:1
so 1.17 / 14.7 = .07959 kg fuel/minute
Relative density of petrol is 0.72 kg/ltr
.07959 / 0.72 = .11054 l/min
.11054 l /min = 6.6326 l/hr = 1.46 galls/hr
HTH 
This is the "theoretical case" as it assumes a full swept volume and a 14.7 ratio ... as Kevin says .. this just won't happen ....
In reality less volume will pass the MAF so less fuel needed, but ratio will be lower so more fuel needed .... 
good approach Entwood
as I understand you take the density of air at 0 meters altitude , 15 celcius and standard atmospheric pressure.. in my job, assumptions are made from time to time to prepare a base calculation.. However, inside engine, air temperatures will change seriously (depending also on weather temp,humidty etc also combustion efficiency may highly change the values) so real injection amounts corrected by ECU from lambda combustion result readings..
so real values may change even 30% from calculated..
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Topic: Something is puzzling me (Read 2879 times)