Print

Please login or register.
1 Hour 1 Day 1 Week 1 Month Forever
Login with username, password and session length

[Terbs]

Hi all
This might be an easy fix for the skilled...I am not fully skilled...

Scenario is....I have a 10' x 7' concrete base for a shed. I am making a base for the shed. All the wood I have cut on my electric bench saw/mitre saw. it is all correct lengths.
I have used 25 x 38 timber as bearers, and screwed them together.
How can I make sure this base is square before I start nailing on the boards, and maintain that squareness. The shed has an overlap on all sides, so the base is made exact size.
I would just add, that putting 45 degree corner pieces in would not be foolproof, as I lent my Mitre saw to my son and it has come back in a different state to what it left here !!!!!! ........So I cannot guarantee the exactness of the angles.

Probably stupid question, but whatever

[jonathanh]

measure both diagonals and make sure they are the same length - they should be 12ft 2.5 inches

[Gaffers]

Then fit right angled brackets in the corner that are flush with the woodwork

[Terbs]

Thanks guys.....
Just one minor point....the actual shed bearer overall size is 80 3/4" x 83 1/8"

How the heck do you know what the corner to corner measurement is supposed to be...you are a genius
Incidently, mine was a inch difference.

Tony

[henryd]

Thanks guys.....
Just one minor point....the actual shed bearer overall size is 80 3/4" x 83 1/8"

How the heck do you know what the corner to corner measurement is supposed to be...you are a genius
Incidently, mine was a inch difference.

Tony

the Measurement is not important,so long as both diagonal measurements are the same its gotta be square

[bigegg]

course, a much easier way is to board the floor with plywood - factory edges are usually square enough that you can square up your beams with the edges of the sheet.

[Entwood]

Thanks guys.....
Just one minor point....the actual shed bearer overall size is 80 3/4" x 83 1/8"

How the heck do you know what the corner to corner measurement is supposed to be...you are a genius
Incidently, mine was a inch difference.

Tony

Right angle triangle either use Pythagoras theorem or basic trigonometry ..

If the sides are 80.75 and 83.125  (80 3/4 x 83 1/8 )

then diagonal is sq rt of  80.75 squared + 83.125 squared .. or sq rt of 6520.5625 + 6909.765625 = sq rt 13430.32813 = 115.8892925 = 9ft  7 4/5 inches

so if both diagonals measure 9 ft 7 4/5 the box is perfectly square ..

[Terbs]

Yeah...I appreciate that bigegg, but I have loads of boards here 19mm x 5 " wide, which were the roof of my old shed. Trying to be a good citizen and recycle

[Terbs]

Thanks guys.....
Just one minor point....the actual shed bearer overall size is 80 3/4" x 83 1/8"

How the heck do you know what the corner to corner measurement is supposed to be...you are a genius
Incidently, mine was a inch difference.

Tony

Right angle triangle either use Pythagoras theorem or basic trigonometry ..

If the sides are 80.75 and 83.125  (80 3/4 x 83 1/8 )

then diagonal is sq rt of  80.75 squared + 83.125 squared .. or sq rt of 6520.5625 + 6909.765625 = sq rt 13430.32813 = 115.8892925 = 9ft  7 4/5 inches

so if both diagonals measure 9 ft 7 4/5 the box is perfectly square ..

 

Geez....I went to school in 1952 - 1962......where the 'ell did that lot come from

[Entwood]

You must have done "the square on the hypotenuse is equal to the sum of the squares of the other two sides" .. basic Pythagorus ...     I think I did that at O level in 1965 ...

[aaronjb]

Was it still wax tablets for notes back then?

[Terbs]

You must have done "the square on the hypotenuse is equal to the sum of the squares of the other two sides" .. basic Pythagorus ...     I think I did that at O level in 1965 ...

Never did 'O' levels.....
Left school when I was 14 (due to school year dates)
Have heard of the quotation though. As to sussing it....beyond me

[Terbs]

Was it still wax tablets for notes back then?

Not digressing from my original post, but....
When I started school it was slates and chalk, till the second class...then pencils. then pen and ink with wooden handled pens and crappy nibs. Last class (aged 10) they invented cartridge pens and we could use them. I have never looked back.
Incidently, biro's were a massive no no.

[MR MISTER]

Thanks guys.....
Just one minor point....the actual shed bearer overall size is 80 3/4" x 83 1/8"

How the heck do you know what the corner to corner measurement is supposed to be...you are a genius
Incidently, mine was a inch difference.

Tony

Right angle triangle either use Pythagoras theorem or basic trigonometry ..

If the sides are 80.75 and 83.125  (80 3/4 x 83 1/8 )

then diagonal is sq rt of  80.75 squared + 83.125 squared .. or sq rt of 6520.5625 + 6909.765625 = sq rt 13430.32813 = 115.8892925 = 9ft  7 4/5 inches

so if both diagonals measure 9 ft 7 4/5 the box is perfectly square ..

Or perfectly rectangular.

[Sir Tigger KC]

Was it still wax tablets for notes back then?

Not digressing from my original post, but....
When I started school it was slates and chalk, till the second class...then pencils. then pen and ink with wooden handled pens and crappy nibs. Last class (aged 10) they invented cartridge pens and we could use them. I have never looked back.
Incidently, biro's weren't invented.

Fixed!