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[TheBoy]

This experiment is to create magnets so powerful that it can affect matter at the atomic level.

Thats already done, pop down your local hospital for a demo.

Yup, but think on a larger scale

[Marks DTM Calib]

This experiment is to create magnets so powerful that it can affect matter at the atomic level.

Thats already done, pop down your local hospital for a demo.

Yup, but think on a larger scale

In which case hes a scientist and not an engineer lol....

When you can go to some hospitals and find 7 Tesla fast switching magnets.....whcih are leading edge with billions of dollars of research behind them.....

[TheBoy]

This experiment is to create magnets so powerful that it can affect matter at the atomic level.

Thats already done, pop down your local hospital for a demo.

Yup, but think on a larger scale

In which case hes a scientist and not an engineer lol....

When you can go to some hospitals and find 7 Tesla fast switching magnets.....whcih are leading edge with billions of dollars of research behind them.....

He's one of the engineers who have to build the shite that the scientists come up with .  I suspect by its nature there is some crossover, where the scientistics have to be (almost) engineers, and the engineers are infected with the scientists

[Rods2]

I would have thought the place to start is by doing some calculations.

R = V / I, so to use 12v at 900A requires a maximum resistance of R = 0.013ohms

Standard coax has a DC resistance of 6.7ohms/km or 0.0067ohms/m, so you need 2m for the experiment.

Power per second = I^2  * R, so 900 * 900 * 0.013 = 10.53kw

But as you only need a pulse of 20ms,  Power used = 10530 * 20 / 1000 = 210w. This is 1w per cm of the coax length.

I can't see why this would be a problem. Longer pulses, like the relay contacts welding together may require a visit from the local fire service at 10.53kw / second. 

[Marks DTM Calib]

Given the (required but not achievable using a relay/contactor) short pulse duration, as the length increases then the capacitance will become an issue to as the system is scaled up for longer lengths.

[Marks DTM Calib]

I would have thought the place to start is by doing some calculations.

R = V / I, so to use 12v at 900A requires a maximum resistance of R = 0.013ohms

Standard coax has a DC resistance of 6.7ohms/km or 0.0067ohms/m, so you need 2m for the experiment.

Power per second = I^2  * R, so 900 * 900 * 0.013 = 10.53kw

But as you only need a pulse of 20ms,  Power used = 10530 * 20 / 1000 = 210w. This is 1w per cm of the coax length.

I can't see why this would be a problem. Longer pulses, like the relay contacts welding together may require a visit from the local fire service at 10.53kw / second. 

It wont get near that level of current though due to the internal resistance of the battery plus connection resistances. 

[Kevin Wood]

It wont get near that level of current though due to the internal resistance of the battery plus connection resistances. 

Yep, it's going to take more than a single car battery.

Now, a submarine battery... http://www.relocationspecialists.org/bat/cell.html

The video's worth a look.